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<title>Electricity Primer Projects </title>
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<h3>
Electricity Primer  Projects
</h3>



<p>

Work is a force times a displacemnt.  The simpelest example is when lifts
an object weighing one pound one foot.  One foot pound of work is done.
Also a torque times an angular displacement is work.
Another example is when a pressure moves a volume of gas or liquid.
Electric charge is just like matter or energy, it is not created or
destroyed.  Maslama al-Majriti in Al-Andalus(later called Iberia)
<a href="http://www.muslimheritage.com/">
first established conservation of mass about 1000 CE.</a>
(later by Lavoisier )  The conservation of energy was established by  
<a href="http://en.wikipedia.org/wiki/Benjamin_Thompson"> Count Rumford, </a>
who studied the mechanical equivalent of heat while boring out cannons.
He also invented the double boiler and percolator coffee pot.
Kirchhoff's Law is the conservation of electric charge.
<a href="http://en.wikipedia.org/wiki/Kirchhoff%27s_circuit_laws">
Gustav Kirchhoff </a> was from Konigsberg.  The electromotive force or
voltage in units of Volts is the force.  The force moves or displaces the
charge at a rate of current in units of Amperes.  Ohm's
<a href="http://www.ibiblio.org/kuphaldt/electricCircuits/"> law </a>
is that a resistance, in units of Ohms,
opposes the flow of current with a force or voltage equal to the flow or
current in units of Amperes times the resistance in units of Ohms.

</p>

` E=IR ` <!-- &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; -->

<img src="space_8-trans.png"> </img>

` P=I^2 R `<p></p> <!-- &nbsp; --> ` W=Pt `
<p> where 
  E is in Volts,
  P is in Watts,
  I is in Amperes,
  R is in Ohms,
  W is in Watt hours, 
  t is in hours,
</p>
` I_1 = \sqrt(P/R) `
<p>

Now taking a great leap to equations found in the National Electrical Code,
an expression relating to the power required by multiple welders with
a duty cycle factor X is:


</p>
<p>


` I_e = \sqrt(I_1^2*X - I_0^2*(1-X) ) `
ref: NEC2008, NFPA Quincy MA, 630.12(B)


<!-- 240.92(B)(2)
  (I^2/A^2)t = 0.0125 log_10((T_2 + 228)/(T_1  -228))  -->

</p>

An expression relating to the time and temperature of insulation:<p></p>
`  (I^2/A^2)t = 0.0125*log_10((T_2+228)/(T_1 -228)) `
ref: NEC2008 240.92(B)(2)

<p>

A battery that has internal resistance will exhibit voltage drop
when increased current is drawn. A standard is the
<a href=""> No. 6 ignition </a> dry cell can have an internal resistance of
0.02 Ohms and an initial, flash amperage, current of 26 Amperes.
</p>




<p> <div id="legendary" name="legendary" style=" position:relative;  
    top:0; left:0;   "  width="282" height="400" >
    POWER LIMITED CLASSES

<embed src="scale_v.svg" style="position:absolute; top:0; left:0; z-index:2 "
     type="image/svg+xml" width="28" height="282" ></embed>

<embed src="scales_3-trans.png" style="position:absolute; top:200; left:28; z-index:1 "
      width="282" height="60" alt="scales" ></embed>

<embed name="pwrlmted" id="pwrlmted" width="400" height="566" src="d.svg"
 style=" position:absolute;  top:0; left:28;  z-index:3;
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 script='initPicture(-1.0,3.0,-2.5,3.0)
 axes(1,1,"labels","grid")
 strokewidth = 1.5
 stroke = "blue"


  line([0.0,3.0],[3.0,0.0])           // 1 kW
  line([0.0,2.3979],[2.3979,0.0])     //  250 W

  line([-0.7976,0.9115],[0.0,0.1139])
  line([0.1139,0.0],[0.0,0.1139])   //  1.3 mW
  line([0.1139,0.0],[0.2278,-0.1139])
  line([0.2278,-0.1139],[0.9115,-0.7976])

//  line([-1.6021,0.0],[0.0,-1.6021])   //  25 mW
  line([-0.8010,-0.8010],[0.0,-1.6021])   //  25 mW


  line([0.0,-1.6021],[0.8010,-2.4031])   //  25 mW
//  line([0.0,-1.6021],[1.6021,-3.2041])   //  25 mW

  line([0.1,0.6990],[1.6,0.6990])     // 5 A
  line([0.1,0.9031],[1.4,0.9031])     // 8 A

  line([1.4771,-2.3010],[1.4771,0.6])    // 30 V
  line([1.7781,-2.3010],[1.7781,0.4])    // 60 V

  line([2.1761,-2.3010],[2.1761,0.1])    // 150 V

  line([1.4771,-2.3010],[2.1761,-2.3010] )  //  5 mA
 stroke = "blue"
//   line([1.4771,-.3010],[2.1761,-.3010] )  500 mA
   line([-1.0,-1.0],[-0.5229,-1.0])    //   100 mA
   line([0.0,-1.0],[0.1761,-1.0])    //   100 mA
   line([0.1761,-1.0],[0.1761,-1.0969])    //   1.5 V
   line([0.1761,-1.6990],[0.1761,-2.3010])    //   1.5 V
 stroke = "blue"


// two No.6 ignition cells          0.06 Ohm per cell
// plot("2.6-x*(2.6/0.3)")
//   circle([0.15,1.3],.05)
//  26 A  3.0 V  I = 26 - y * (26/3)
//                      y = exp(x)
//      log(I) = log(26 - (26/3) exp(x))    -0.01,0.4771
   plot("(log(26 - (26/3)  * exp(x* 2.302)))/2.302",-1.0,0.4771)

// car battery         1.079
   plot("(log(450 - (450/12) * exp(x* 2.302)))/2.302",-1.0,1.079)
//  intrinsic 1.3 W
// simple 25mW   1.5 V 100 mA
//   plot("(log(0.1 - (0.1/1.5) * exp(x* 2.302)))/2.302",-1.0,0.4771)
// AA cell   12.5 A flash
   plot("(log(12.5 - (12.5/1.5) * exp(x* 2.302)))/2.302",-1.0,0.4771)

 text([1,2],"power limit = 1 kW ",aboveright)
 text([2.5,0],"log(Voltage/1 Volt) ",above)

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  line([0.6990,-0.1],[0.6990,0.1]) 
  line([0.9031,-0.1],[0.9031,0.1]) 


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  line([-0.1,0.6990],[0.1,0.6990]) 
  line([-0.1,0.9031],[0.1,0.9031]) 

 '>      </embed>

</div></p>




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<p><img src="spacer.gif"></img></p><p>.</p><p>.</p>
A 12 Volt lead acid battery used in an automobile can deliver 180 Watts/kg
or a 450 A flash current.


<!-- http://www.answers.com/topic/lead-acid-battery-1
http://www.prc68.com/I/batt.shtml     www.batteryfaq.org
http://www.powerstream.com/Size_SLA.htm  12V 80 Ahr 31kg=68lb    450A flash

http://data.energizer.com/PDFs/BatteryIR.pdf
   AA  0.12 Ohm   12.5 A flash
 -->




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  line([0,1.00],[-.87,-.50])
  dot([0,1.00],closed,"208j",above)




 strokewidth = 1


//  black center  (0.43,0.25)   2(0.087,0.05)=(0.171,0.1)
  stroke = "black"
  line([0,0],[.87,-.50])
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  line([0,0],[-.87,-.50])
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   text([0,-.70],"240 V")
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//  line([0.6,0.35],[1.03,-.4])
  line([0.7,0.18],[1.03,-.4])
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  arc([1.1,0.33],[0.33,1.1],1.319)
   text([1.0,0.9],"60 cps")


 text([-1,-1.05],"Argand diagram or Nyquist plot",belowright)'>
 </embed><p></p>

<!--   a xlink:href="http://en.wikipedia.org/wiki/"       right)?    -->

<p>
The way in which the three wires with 3 phase power are connected
to 3 phase motors effects the direction in which the motor turns.
Attempts to coordinate this in more than one building, to enable
cord and plug movement require some
<a href="http://www.allaboutcircuits.com/vol_2/chpt_10/3.html"> standardization </a>
and <a href="http://www.opamp-electronics.com/tutorials/phase_rotation_2_10_03.htm">measurement.</a>
Definitions and conventions,e.g. NEC2008 409.102,408.3(E),as well are
needed.

Three phase power can be derived from two phase power but not without
an idler motor or and active compensating device or reactive devices
that have to be adjusted for the amount of power required.

</p>
<p>

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